2014年2月23日星期日

Latest training guide for EC-COUNCIL 312-49

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Exam Code: 312-49
Exam Name: EC-COUNCIL (Computer Hacking Forensic Investigator )
One year free update, No help, Full refund!
Total Q&A: 150 Questions and Answers
Last Update: 2014-02-23

312-49 Free Demo Download: http://www.itcertking.com/312-49_exam.html

NO.1 When an investigator contacts by telephone the domain administrator or controller listed by a
whois lookup to request all e-mails sent and received for a user account be preserved, what
U.S.C. statute authorizes this phone call and obligates the ISP to preserve e-mail records?
A. Title 18, Section 1030
B. Title 18, Section 2703(d)
C. Title 18, Section Chapter 90
D. Title 18, Section 2703(f)
Answer: D

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NO.2 It takes _____________ mismanaged case/s to ruin your professional reputation as a computer
forensics examiner?
A. by law, three
B. quite a few
C. only one
D. at least two
Answer: C

EC-COUNCIL   312-49 test answers   312-49

NO.3 Before you are called to testify as an expert, what must an attorney do first?
A. engage in damage control
B. prove that the tools you used to conduct your examination are perfect
C. read your curriculum vitae to the jury
D. qualify you as an expert witness
Answer: D

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NO.4 You are working for a large clothing manufacturer as a computer forensics investigator and are
called in to investigate an unusual case of an employee possibly stealing clothing designs from
the company and selling them under a different brand name for a different company. What you
discover during the course of the investigation is that the clothing designs are actually original
products of the employee and the company has no policy against an employee selling his own
designs on his own time. The only thing that you can find that the employee is doing wrong is that
his clothing design incorporates the same graphic symbol as that of the company with only the
wording in the graphic being different. What area of the law is the employee violating?
A. trademark law
B. copyright law
C. printright law
D. brandmark law
Answer: A

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NO.5 The offset in a hexadecimal code is:
A. The last byte after the colon
B. The 0x at the beginning of the code
C. The 0x at the end of the code
D. The first byte after the colon
Answer: B

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NO.6 How many characters long is the fixed-length MD5 algorithm checksum of a critical system file?
A. 128
B. 64
C. 32
D. 16
Answer: C

EC-COUNCIL   312-49   312-49

NO.7 What does the superblock in Linux define?
A. file system names
B. available space
C. location of the first inode
D. disk geometry
Answer: B, C, D

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NO.8 The newer Macintosh Operating System is based on:
A. OS/2
B. BSD Unix
C. Linux
D. Microsoft Windows
Answer: B

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NO.9 A honey pot deployed with the IP 172.16.1.108 was compromised by an attacker . Given below is
an excerpt from a Snort binary capture of the attack. Decipher the activity carried out by the
attacker by studying the log. Please note that you are required to infer only what is explicit in the
excerpt. (Note: The student is being tested on concepts learnt during passive OS fingerprinting,
basic TCP/IP connection concepts and the ability to read packet signatures from a sniff dump.)
03/15-20:21:24.107053 211.185.125.124:3500 -> 172.16.1.108:111
TCP TTL:43 TOS:0x0 ID:29726 IpLen:20 DgmLen:52 DF
***A**** Seq: 0x9B6338C5 Ack: 0x5820ADD0 Win: 0x7D78 TcpLen: 32
TCP Options (3) => NOP NOP TS: 23678634 2878772
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.452051 211.185.125.124:789 -> 172.16.1.103:111
UDP TTL:43 TOS:0x0 ID:29733 IpLen:20 DgmLen:84
Len: 64
01 0A 8A 0A 00 00 00 00 00 00 00 02 00 01 86 A0 ................
00 00 00 02 00 00 00 03 00 00 00 00 00 00 00 00 ................
00 00 00 00 00 00 00 00 00 01 86 B8 00 00 00 01 ................
00 00 00 11 00 00 00 00 ........
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.730436 211.185.125.124:790 -> 172.16.1.103:32773
UDP TTL:43 TOS:0x0 ID:29781 IpLen:20 DgmLen:1104
Len: 1084
47 F7 9F 63 00 00 00 00 00 00 00 02 00 01 86 B8 G..c............
00 00 00 01 00 00 00 01 00 00 00 01 00 00 00 20 ...............
3A B1 5E E5 00 00 00 09 6C 6F 63 61 6C 68 6F 73 :.

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